CENTRAL AGGREGATE LOSS MODEL
Bill Adongo’s Manuscript:
“In Actuarial practices, aggregate loss distribution is used
extensively in all practical fields such as ratemaking, premium making and
developing of loss distributions and models. Aggregate models include portfolio
aggregate loss models, aggregate variance methods, fast fouries transformation,
aggregate life model etc. to open the development of the central aggregate loss
models I must start with the central variance method first.
Theorem(1):
If the pgf of the secondary distribution of S is var(si)=∑µiσi,
the distribution Si,….,Sn would have independent compound
distribution X~Sn[p(t)] with µi=[1-p(t)]/p(t) and σi=[1-p(t)]/p(t)2.
Also, the distribution Si,….., Sn would have independent
compound distribution with µi2=var(s)/2σn and σi=Var(s)/2µn.
Example(1):
Let var(s)=88, and X~Sn(0.4). Compute µx,
σx2 and σn, µn.
SOLUTION
µi=[1-p(t)]/p(t)=0.6/0.4=1.50
σi=[1-p(t)]/p(t)2=0.6/0.42=1.43
σn=var(s)/2µx2=88/2(1.52)=19.56
µn=var(s)/2√σx=88/2√1.43=36.79
Theorem(2):
If the pgf of the secondary distribution of S is p(t)=∑wip(t)
where wi=λi/λ, the distribution Si,…., Sn
would have independent compound posson distribution with parameters λ=λi
and p(t)=p(t)/2wi.
Theorem(3):
Given the secondary distribution which has expectation of x
is E(X)=∑piµi where pi=E(X)/2µi,
the distribution of the variance would expressed us:
Var(x)=∑E(X)/2µi[(µi-µ)2+σ2]
Example(2):
The claim frequency of a bad driver is distribution at
PN(4), and the claim frequency of a good driver is distributed as PN(1), If the
expected value is 1.6; what is the
probabilities and variance of the good and bad driver.
Pgood=E(X)/2µgood=1.6/2(1)=0.8
Pgood=E(x)/2µbad=1.6/2(4)=0.2
Var(x)=1.6/2(4)[(4-1.6)2+4]+1.6/2(1)[(1-1.6)2+1]
Var(x)=0.2X9.76+0.8X1.36
Var(x)=3.04”
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